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X^4/3-7x^2/3+10=0 what is x

1 Answer

4 votes
Solve for x:10 - (7 x^2)/3 + X^4/3 = 0
Subtract X^4/3 + 10 from both sides:-(7 x^2)/3 = -X^4/3 - 10
Multiply both sides by -3/7:x^2 = X^4/7 + 30/7
Take the square root of both sides:Answer: x = sqrt(X^4/7 + 30/7) or x = -sqrt(X^4/7 + 30/7)