Question

An ideal gas undergoes an adiabatic process and does 25 joules of work on its environment. What is the change in internal energy? a.50 joules b. 25 joules c. 0 joules d. -25 joules

Answer 1

using Δh = q+w
under adiabatic conditions q = 0
w= 25joules
Δh= 25joules

Answer 2

The change in internal energy will be 25 J.

Step-by-step explanation:

Given that,

Work done = 25 J

Using first law of thermodynamics

The internal energy is sum of the heat and work done.

`\Delta U= Q+ W`

Where,
`\Delta U` = Change in internal energy

Q = heat

W = work done

In adiabatic process, the heat does not change, it remains constant.

So the heat Q = 0

Therefore, The change in internal energy will be

`\Delta U=0+25 J`

`\Delta U= 25 J`

Hence, The change in internal energy will be 25 J.