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Find the values of x which satisfy: 2(4^2x)-3(4^x)+1=0

User Ytsejam
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1 Answer

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First let X = 4^x, then we have:-
2X^2 - 3X + 1 = 0

(2X - 1)(X - 1) = 0

X = 0.5 , 1

So 4^x = 1 which makes x = 0

and 4^x = 0.5 gives x ln4 = ln0.5 so x = ln0.5 / ln 4 = -0.5

Solution set is (-0.5,0)

User Xphong
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