Question

Write the equation of a line that is parallel with a y = -2/3 x + 2 and goes

through the point (-3,0).

Answer 1

y = -2/3x - 2

Explanation:

Parallel lines have the same slope so slope = -2/3

Given (-3,0)

Slope-intercept: y = mx + b

0 = -2/3(-3) + b

0 = 2 + b

b = -2

then y = -2/3x - 2