5) x represents the widgets; y represents the gadgets
Widgets are $3 each ; gadgets are $5 each.
The boss wants AT LEAST 10 widgets and 20 gadgets and total must reach AT MOST $300 per day.
Your inequalities would be:
x ≥ 10 (there must be greater than or equal to 10 widgets made)
y ≥ 20 (there must be greater than or equal to 20 gadgets made)
3x + 5y ≤ 300 (the cost must be less than or equal to 300)
The solution is H.
6) Solve for all possibilities.
I) f(k) + g(k)
= -4k⁴ + 14 + 3k² + (-3k⁴ - 14k² - 8)
= -4k⁴ + 14 + 3k² - 3k⁴ - 14k² - 8
Combine like terms.
= -7k⁴ - 11k² + 6
II) h(k) - r(k)
= 8k⁴ - 3 - 10k² - (-k² + 12k⁴ + 6)
= 8k⁴ - 3 - 10k² + k² - 12k⁴ - 6
= -4k⁴ - 9k² - 9
III) s(k) - t(k)
= -3k⁴ + 5k² - 1 - (4k⁴ + 16k² - 7)
= -3k⁴ + 5k² - 1 - 4k⁴ - 16k² + 7
= -7k⁴ - 11k² + 6
There are only two that result in equivalent expressions which are I and III.
Solution : I and III.