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What is the equation of the graph below?Oy=-(x-3)²-2Oy=-(x + 2)²-3Oy=(x-3)²-2Oy=(x + 2)²-3

What is the equation of the graph below?Oy=-(x-3)²-2Oy=-(x + 2)²-3Oy=(x-3)²-2Oy=(x-example-1
User Mete Atamel
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1 Answer

20 votes
20 votes

Given: The parabola shown

To Determine: The equation of the parabola

Solution

The equation of a parabola given the vertex and a point is given as


\begin{gathered} y=a(x-h)^2+k \\ Vertex=(h,k) \\ a=stretch-constant \end{gathered}

From the graph, we locate the vertex and the a point A as shown below

So


\begin{gathered} Vertex=(3,-2) \\ PointA:(4,-1) \end{gathered}

Substitute the vertex and the point A to get the value of a


\begin{gathered} y=a(x-h)^2+k \\ -1=a(4-3)^2+(-2) \\ -1=a(1)^2-2 \\ -1=a-2 \\ -1+2=a \\ 1=a \end{gathered}

Substitute the value of a and the vertex to get the equation of the parabola


\begin{gathered} y=a(x-h)^2+k \\ y=1(x-3)^2+(-2) \\ y=(x-3)^2-2 \end{gathered}

Hence, the equation of the parabola is

y = (x -3)² - 2

What is the equation of the graph below?Oy=-(x-3)²-2Oy=-(x + 2)²-3Oy=(x-3)²-2Oy=(x-example-1
User Kforjan
by
3.0k points
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