Answer:
In Point Form: (x,y,z)= (3,6,-1)
In Equation Form: x=3, y=6, z=-1
Explanation:
1) Solve for x
2x+2z=4 (Subtract 2z from both sides)
-2z -2z
2x= 4-2z (Divide 2 from both sides)
/2 /2
x=2-z
2) Substitute 2-z for x in
-x-y-z=-8
-(2-z)-y-z=-8
-2+z-y-z=-8 (Combine Like Terms)
-2-y=-8 (Add 2 to both sides)
+2 +2
-y=-6 (Divide -1 from both sides)
/-1 /-1
y=6
3) Substitute 2-z for x & 6 for y in
-4x+4y+5z+=7
-4(2-z)+4(6)+5z=7 (Get rid of parentheses)
-8+4z+24+5z=7 (Combine Like Terms)
9z+16=7 (Subtract 16 from both sides)
-16 -16
9z+=-9 (Divide 9 from both sides)
/9 /9
z=-1
4) Now find x by substituting -1 for z in
x=2-z
x=2-(-1)
x=2+1
x=3
Therefore the answer is:
In Point Form: (x,y,z)= (3,6,-1)
In Equation Form: x=3, y=6, z=-1