Question

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t^2 +19.6t + 58.8. What is the object's maximum height?

Answer 1

rewrite the equation in vertex form
-4.9(t - 2)^2 - 4) + 58.8
= -4.9(t - 2)^2 + 19.6 + 58.8

= -4.9( t - 2)^^2 + 78.4

Maximum height = 78.4 m