Question

The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

Answer 1

Harold used
x1 = 7
and y1 = 0
the points are (7,0)

Answer 2

Answer: equation of a linear function in point-slope form

Explanation:

Given : The equation of a linear function in point-slope form passing through point
`(x_1,y_1)` is

`y -y_1 = m(x -x_1)`

The equation written by Harold correctly

`y = 3(x - 7)`

It can be written as:
`y-0 = 3(x - 7)`

When we compare to the equation of a linear function in point-slope form, we get
`y_1=0,\ x_1=7`

Hence, the point used by Harold =
`(x_1,y_1)=(7,0)`