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What is the vertex of the function x^2-6x+8=0 ?
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3 votes
What is the vertex of the function x^2-6x+8=0 ?

User Vladislavs Dovgalecs
by
8.9k points

1 Answer

4 votes
-6 / 2 = -3 so
x^2 - 6x + 8 is
(x - 3)^2 -9 + 8

= (x - 3)^2 - 1


the vertex is at (3,-1)
User Maulik Suchak
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7.8k points
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