208k views
3 votes
What is the vertex of the function x^2-6x+8=0 ?

1 Answer

4 votes
-6 / 2 = -3 so
x^2 - 6x + 8 is
(x - 3)^2 -9 + 8

= (x - 3)^2 - 1


the vertex is at (3,-1)
User Maulik Suchak
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.