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What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15? Enter your answer in the box

User MarLeo
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2 Answers

5 votes

Answer:

3x+4y=16

Clarifying because other explanation was confusing

Just took review

Explanation:

What is the equation of a line that passes through the point (8, −2) and is parallel-example-1
User Dave Morse
by
7.8k points
3 votes

Step 1

Find the slope of the given line

we have


3x+4y=15

Isolate the variable y

Subtract
3x both sides


3x+4y-3x=15-3x


4y=-3x+15

Divide by
4 both sides


y=-(3)/(4)x+ (15)/(4)

the slope of the given line is


m=-(3)/(4)

Step 2

Find the equation of the line that passes through the point
(8,-2) and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to


y-y1=m(x-x1)

we have


m=-(3)/(4)


(x1,y1)=(8,-2)

substitute in the equation


y+2=-(3)/(4)(x-8)


y=-(3)/(4)x+6-2


y=-(3)/(4)x+4 or
3x+4y=16

therefore

the answer is


y=-(3)/(4)x+4

or


3x+4y=16

User Faheem Kalsekar
by
9.2k points

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