What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x4+5 ? Enter your answer in the box.

Question

asked Jun 27, 2018 191k views

2 Answers

← Prev Question Next Question →

Ask a Question

Kmarabet · Answer 1 · 2018-06-30T12:02:54+0000

y = x/4 + 5, slope = 1/4

perpendicular lines, slope is opposite and reciprocal
so slope = -4

passes through the point (2, 7)
y = mx + b
b = y - mx
b = 7 - (-4)(2)
b = 7 + 8
b = 15

equation
y = -4x + 15

answer
y = -4x + 15

What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x4+5 ? Enter your answer in the box.

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

No related questions found

Categories

Other Questions