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What is the equation for the line of reflection that maps the trapezoid onto itself? x = 0 x = 3 y = 3 y = 0?

User MinuteMed
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Answer: it's actually x=3

Explanation:

just took the test :]

User Kliew
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The given trapezoid has a line of symmetry that is at the midpoint of the base of the tapezoid.

Given that the base of the trapezoid runs from point (-3, 2) to point (7, 2), the midpoint is given by (-3 + 7) / 2 = 4 / 2 = 2.

Thus, the line of refrection the maps the trapezoid onto itself is x = 2.
What is the equation for the line of reflection that maps the trapezoid onto itself-example-1
User Goldbullet
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