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Is it possible to compress an ideal gas isothermally in an adiabatic piston–cylinder device? explain?

User Henryyao
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Answer: Since, Q = U+W (Q-W = U) With adiabatic, Q =0 If some work is done then, U will be non zero. And since U is internal energy change it should result in a temperature change. With isothermal process we are also saying U=0 but that would imply that W=0. However we did work since compression requires work to be done. So it is not possible.
User Nitish Parkar
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