Question

PLEASE HELP!!!!

Suppose the tree diagram below represents all the students in a high school and that one of these students were chosen at random. If the student is known to be a girl, what is the probability that the student is right-handed?



A. 1/4
B. 3/4
C. 5/6
D. 1/6

Answer 1

The probability that the student is right-handed given that the student is a girl is:

`(5)/(6)`

Explanation:

From the tree diagram we have to find the probability that the students is right handed given that the student is a girl.

Let A denote the event that the student is a girl.

and B denote the event that the student is right handed.

We are asked to find the probability:

P(B|A)

We know that P(B|A) is calculated as:

`P(B|A)=(P(A\bigcap B))/(P(A))`

There are a total of 500 students.

Out of which 300 are girls.

( i.e.
`P(A)=(300)/(500)=(3)/(5)` )

and out of 300 girls 250 are right handed.

( i.e.
`P(A\bigcap B)=(250)/(500)=(1)/(2)` )

Hence,

`P(B|A)=((1)/(2))/((3)/(5))\\\\\\P(B|A)=(5)/(6)`

Hence,The probability that the student is right-handed given that the student is a girl is:

`(5)/(6)`

Answer 2

The Answer is C 5/6

250/300 reduced and simplified is 5/6