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2 votes
A. Find the value of a. b. Find the value of the marked angles.

A)14; 94°

B)16; 106°

C)19; 124°

D)15; 100°

A. Find the value of a. b. Find the value of the marked angles. A)14; 94° B)16; 106° C-example-1
User Lazyboy
by
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2 Answers

3 votes
a=15 and the angles are 100 degrees. Thats because  6a=10=3a=55 due to alternate angles equal the same angle. so if you algebraically solve for a, you eventually get a=15. then plug in your a value into either or given equations. (i.e.. 6(15)+10= 100
User LearnerEarner
by
6.2k points
5 votes

Answer:

D)15; 100°.

Explanation:

Given : Verticle opposite angles (6a + 10) and (3a + 55).

To find : Find the value of a. b. Find the value of the marked angles.

Solution : We have given (6a + 10) and (3a + 55).

Verticle opposite angles are equal

Then

6a + 10 = 3a + 55

On subtracting both sides by 3a

6a - 3a + 10 = 55

3a + 10 = 55

On subtracting by 10 both sides.

3a = 55 -10.

3a = 45.

On dividing the 3 by both sides

a = 15°.

Then ,

6 (15) + 10.

90 + 10 = 100

b =100°.

Therefore, D)15; 100°.

User Kwagjj
by
7.0k points
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