The reasonable solution is B) 1100 adults and 1400 students, as it satisfies both attendance and revenue criteria.
Consider a movie theater that sells student tickets for $5 and adult tickets for $10. On a Saturday night, 2,500 people attended the theater, and the total ticket sales amounted to $18,000. The goal is to determine the number of adults and students who attended, with multiple choices provided:
We can set up two equations to represent the information:
The total number of people who attended: S + A = 2500
The total ticket sales amount: 5S + 10A = 18000
Solving this system of equations gives the correct solution:
B) 1100 adults and 1400 students.
This solution satisfies both equations (S + A = 2500 and 5S + 10A = 18000). It is reasonable as it accounts for both students and adults attending, and the total revenue aligns with the given information. The number of students (1400) and adults (1100) adds up to the total attendance of 2500.