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Please someone help me this is the second time I posted this question....

What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of −5/6 ?

A. y−4=−5/6(x−8)
B. y+4=−5/6(x−8)
C. y−4=−5/6(x+8)
D. y+4=−5/6(x+8)
Please provide an explanation on how to do this.

1 Answer

3 votes

\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 8}}\quad ,&{{ -4}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -\cfrac{5}{6} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-4)=-\cfrac{5}{6}(x-8) \\\\\\ y+4=-\cfrac{5}{6}(x-8)
User Thinh
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