Question

The length of a rectangle is 5 m less than double the width, and the area of the rectangle is 33 m^2 . Find the dimensions of the rectangle.

Please help ASAP!

Answer 1

A = Lw = 33m^2
(2w-5)w = 33
2w^2 - 5w - 33 = 0, w = 5.5m and L = 6
I think

Answer 2

A = L * W
A = 33
L = 2W - 5

33 = W(2W - 5)
33 = 2W^2 - 5W
-2W^2 + 5W + 33 = 0
(-2W + 11)(W + 3) = 0

-2W + 11 = 0
-2W = -11
W = -11/-2
W = 11/2 or 5.5

W + 3 = 0
W = -3.....not this one because it is negative

L = 2W - 5
L = 2(5.5) - 5
L = 11 - 5
L = 6

the dimensions are : length = 6 m and width = 5.5 m <==