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In △ABC, the coordinates of vertices A and B are A(1,−1) and B(3,2). For each of the given coordinates of vertex C, is △ABC a right triangle?

Select Right Triangle or Not a Right Triangle for each set of coordinates.
C(0,2) right triangle or not a right triangle?
C(3,-1) right triangle or not a right triangle?
C(0,4) right triangle or not a right triangle?

User Mark Hall
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2 Answers

4 votes

Final answer:

To determine if △ABC is a right triangle, we can use the distance formula to calculate the lengths of the sides of the triangle. By comparing the squares of these lengths, we can determine if △ABC is a right triangle. For the given coordinates of vertex C, △ABC is not a right triangle.

Step-by-step explanation:

To determine if △ABC is a right triangle, we need to check if the square of the length of the longest side is equal to the sum of the squares of the other two sides. Using the distance formula, we can find the lengths of AB and AC for each set of coordinates for vertex C. We then compare the squares of these lengths to determine if △ABC is a right triangle.

For C(0,2), the distance between A(1,-1) and C is √((0-1)^2 + (2-(-1))^2) = √(1 + 9) = √10. The distance between B(3,2) and C is √((0-3)^2 + (2-2)^2) = √(9 + 0) = 3. The longest side is AB with length √(2^2 + 3^2) = √(4 + 9) = √13. Since √13 is not equal to √10 + 3, △ABC is not a right triangle.

Following the same calculations for C(3,-1) and C(0,4), we find that △ABC is also not a right triangle for both cases. Therefore, the answer for all three sets of coordinates is Not a Right Triangle.

User Smilexu
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8.0k points
4 votes

Answer:

C(0,2) - Not A Right Angle

C(3,-1) - Right Angle

C(0,4) - Right Angle


I took the unit test and after this was the correct and answer. Hope this helps :))



User Walnut
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