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Calculate the enthalpy change for the reaction: 2 H2O2(l) → 2 H2O(l) + O2(g) using enthalpies of formation: ΔH∘f(H2O2)=−187.8 kJ/mol ΔH∘f(H2O)=−295.8 kJ/mol
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Calculate the enthalpy change for the reaction:

2 H2O2(l) → 2 H2O(l) + O2(g)
using enthalpies of formation:
ΔH∘f(H2O2)=−187.8 kJ/mol
ΔH∘f(H2O)=−295.8 kJ/mol

User Naili
by
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1 Answer

4 votes

Answer:

-196.0 kJ

Step-by-step explanation:

User Qing Xu
by
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