143k views
5 votes
passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to ?

User Caesar
by
7.6k points

2 Answers

4 votes

Answer: -5x -3y = 0

Explanation:

took on edmentum/plato and got it right. enjoy :)

User Eusebio
by
8.1k points
4 votes

Answer:

Equation of line , 5x + 3y = 0

Explanation:

The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by
(y_2-y_1)/(x_2-x_1)

Here points are given by (-3,0) and (-6,5)

Slope
=(5-0)/((-6)-(-3))=(-5)/(3)

The slope of parallel lines are same. So slope of required line
=(-5)/(3)

Equation of a line with slope m passing through origin is given by

y =mx

So equation of line,
y=(-5)/(3)x\\\\3y=-5x\\\\5x+3y=0

Equation of line , 5x + 3y = 0

User Deyan Vitanov
by
7.9k points

No related questions found