Final answer:
The sum of four consecutive even integers that equal 36 is broken down to find the smallest integer. Once the smallest integer is found (6), we can determine that the third largest integer in the sequence is 8.
Step-by-step explanation:
To solve for the third largest integer in a set of four consecutive even integers that sum to 36, we can define the smallest integer as x. The next integers would be x + 2, x + 4, and x + 6. Setting up the equation:
x + (x + 2) + (x + 4) + (x + 6) = 36
Combining like terms, we get:
4x + 12 = 36
Subtracting 12 from both sides:
4x = 24
Dividing by 4:
x = 6
Now we have our integers: 6, 8, 10, 12. The third largest integer, which is the second smallest, is 8.