Given that f(x)=-x^2+6x-1
f(1) = - 1^2 + 6(1) - 1
= -1 + 6 -1
= 4
f(3) = -3^2 + 6(3) - 1
= -9 + 18 -1
= 8
Hence
a. f(1) + f(3) = 4 + 8
= 12
b. f(1) - f(3) = 4 - 8
= -4
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