Question

A sample of n2 effuses in 220 s. how long will the same size sample of cl2 take to effuse? a sample of n2 effuses in 220 s. how long will the same size sample of cl2 take to effuse? 86.8 s 388 s 350 s 558 s 138 s

Answer 1

According to Graham's gas effusion law, the rate effusion of N2 is 1.591 times greater than that of Cl2. To find the time, multiply the rate and the time. 220 x 1.591 = 350s.

Answer 2

Answer : The sample of
`Cl_2` effuses in, 350 seconds.

Solution : Given,

Effusion time of
`N_2` = 220 s

Molar mass of
`N_2` = 28 g/mole

Molar mass of
`Cl_2` = 71 g/mole

Rate of effusion : It is defined as the volume of gas effused in a given time 't'.

Formula used :
`Rate=(Volume)/(Time)`

Or,

Rate of effusion : It is defined as the rate of effusion is directly proportional to the square root of the mass of the gas.

`\text{ Rate of effusion}\propto \frac{1}{\sqrt{\text{ Mass of gas}}}`

From the two expressions, we conclude that the relation between the time and the mass of gas is,

`√(M)\propto t`

or,
`\sqrt{(M_1)/(M_2)}=(t_1)/(t_2)` .........(1)

where,

`M_1` = molar mass of
`N_2` gas

`M_2` = molar mass of
`Cl_2` gas

`t_1` = time of effusion of
`N_2` gas

`t_2` = time of effusion of
`Cl_2` gas

Now put all the given values in equation (1), we get

`\sqrt{(28g/mole)/(71g/mole)}=(220s)/(t_2)`

By rearranging the terms, we get

`t_2=349.8s=350s`

Therefore, the sample of
`Cl_2` effuses in, 350 seconds.