Question

An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.

N=?

Answer 1

F = Ke
F = 39200×(25÷100)
F= 9800 N

Answer 2

Answer : F = 9800 N

Explanation :

It is given that,

The spring constant for the industrial scale at the junkyard, k = 39,200 N/m

Displacement of spring, x = 25 cm = 0.25 m

According to Hooke's law, the force applied on spring is given by the following relation :

F = -k x

Negative sign shows the force is applied in opposite direction.

`F = -39,200\ N/m* 0.25\ m`

So,
`F=-9800\ N`

`|F|=9800\ N`

Hence, this is the required solution.