Question

) A motorcycle traveling at 35 m/s steps and the brakes and comes to rest in 4.5 seconds. How far did it take for the motorcycle to come to rest?

Answer 1

In order to determine the distance the motorcycle traveled before he stops, first calculate the acceleration, by using the following formula:

`a=(v-v_o)/(t)`

where,

vo: initial speed = 35m/s

a: acceleration = ?

v: final speed = 0m/s

t: time = 4.5s

replace the previous valuesand simplify:

`a=(0(m)/(s)-35(m)/(s))/(4.5s)\approx-7.78(m)/(s^2)`

As you can notice, the acceleration is negative because the motorcycle is slowing down the speed.

Next, use the following formula:

`x=v_ot+(1)/(2)at^2`

replace the values of the parameters and simplify:

`x=(35(m)/(s))(4.5s)+(1)/(2)(-7.78(m)/(s^2))(4.5s)^2\approx78.72m`

Hence, the motorcycle traveled approximately 78.72m before coming to a stop