Question

What is the point slope form of a line with slope 4/5 that contains the points -2,1

Answer 1

y - y1 = m(x - x1)
slope(m) = 4/5
(-2,1)....x1 = -2 and y1 = 1
now we sub
y - 1 = 4/5(x - (-2) =
y - 1 = 4/5(x + 2) <===

Answer 2

`y-1= (4)/(5) (x+2)`

Explanation:

Using point-slope intercept form:

The equation of line is given by:

`y-y_1 = m(x-x_1)` .....[1]

where,

m is the slope of the line and
`(x_1, y_1)` is the point on the line.

As per the statement:

A line with slope 4/5 that contains the points (-2,1)

⇒m =
`(4)/(5)` and
`(x_1, y_1)=(-2, 1)`

Substitute these values in [1] we have;

`y-1= (4)/(5) (x+2)`

Therefore,
`y-1= (4)/(5) (x+2)` is the point slope form of a line with slope 4/5 that contains the points (-2,1).