Question

What pressure will 14.0 g of co exert in a 3.5 l container at 75°c?

Answer 1

The answer would be 4.1 atm. I am sorry you did not get an answer.

Answer 2

P = 4.0794 atm or 413,345.2 Pa

Step-by-step explanation:

Given

Mass m = 14.0 g

Volume 3.5 L

Temperature T = 75° C = 75 + 273 = 348 K

Known Values

Molar mass of CO = 28 g/mol

Universal gas constant R =
`0.082057 L.atm/mol.K`

Solution

Number of moles in 14 g of CO is

`\\n=(mass)/(molar.mass) \\\\n = (14)/(28) \\\\n = 0.5 mole`

`PV = nRT\\\\P = (nRT)/(V) \\\\P = (0.5 * 0.082057 * 348)/(3.5) \\\\P = 4.0794 atm\\\\P = 4.0794 * 101325\\\\P = 413,345.2 Pa`