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Now consider the example of a positive charge q moving in the xy plane with velocity v⃗ =vcos(θ)i^+vsin(θ)j^ (i.e., with magnitude v at angle θ with respect to the x axis). if the local magnetic field is in the +z direction, what is the direction of the magnetic force acting on the particle?

User Scoob
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Answer:

F⃗ mag =

−cosθj^ + sinθi^

Step-by-step explanation:

use cross product

User Guruprasad J Rao
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