Final answer:
The normal force on a car traveling inside a vertical circular track differs at the top and bottom. At the top, the normal force is in the same direction as gravity, and at the bottom, it supports the car's weight against gravity plus provides the centripetal force. To find the normal force at the bottom, one must use the equations for circular motion taking into account the gravitational force.
Step-by-step explanation:
To determine the normal force on the car at the bottom of the track (point A), we must consider that the car is in circular motion, and at the top and bottom of the track, the forces acting on the car are different due to its position relative to the center of the circular path.
At the top of the track, the normal force and the weight of the car both act downwards. Since the car is in circular motion and is not accelerating vertically, the net force must be equal to the centripetal force required to keep the car moving in a circle. This can be represented by the equation N + mg = mv2/r at point B, where N is the normal force, m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car and r is the radius of the circular path.
At the bottom of the track, the normal force acts upwards while the weight of the car acts downwards. The normal force at the bottom must be greater than at the top because it must support the car's weight in addition to providing the centripetal force. So, the equation at point A is N - mg = mv2/r.
From the information provided, we know that the normal force at the top is 6.00 N, the mass of the car is 0.800 kg, and the gravitational acceleration is 9.8 m/s2. By writing out both equations for the normal force at the top and bottom, and substituting the known values, we can solve for the unknown normal force at the bottom of the track.