Question

(a) Find the terminal voltage (in V) of a 12.0 V motorcycle battery having a 0.610 Ω internal resistance, if it is being charged by a current of 11.5 A. V(b) What is the output voltage (in V) of the battery charger? V

Answer 1

Given:

• Voltage = 12.0 V

,

• Resistance, R = 0.610 Ω

,

• Current, A = 11.5 A

Let's solve for the following:

• (a). Let's find the terminal voltage.

To find the terminal voltage, apply the formula:

`V_T=V+IR`

Thus, we have:

`\begin{gathered} V_T=12.0+(11.5)(0.610) \\ \\ V_T=12.0+7.015 \\ \\ V_T=19.015V \end{gathered}`

Therefore, the terminal voltage is 19.015 V.

• (b). ,What is the output voltage (in V) of the battery charger?

The output voltage will be equivalent to the terminal voltage of the battery.

Therefore, the output voltage of the battery is 19.015 V.

ANSWER:

• (a). 19.015 V

• (b). 19.015 V