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The sum of a number and its reciprocal is 13/6. find the number

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x + (1)/(x) = (13)/(6) \text{, x} \\eq 0

x^(2) - (13)/(6)x + 1 = 0

6x^(2) - 13x + 6 = 0

6x^(2) -9x - 4x + 6 = 0

3x(2x - 3) - 2(2x - 3) = 0

(3x - 2)(2x - 3) = 0

So, the numbers are: 3/2 and 2/3
User Jimmbraddock
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