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Solve 8y-3(4-2y)=6(y+1)

User Moob
by
7.8k points

2 Answers

5 votes
8y − 3(4 − 2y) = 6(y + 1)

Step 1: Simplify both sides of the equation.
8y 3(4 − 2y) = 6(y + 1)
8y + (−3)(4) + (−3)(2y) = (6)(y) + (6)(1) (Distribute)
8y + −12 + 6y = 6y + 6(8y + 6y) + (−12) = 6y + 6 (Combine Like Terms)
14y + −12 = 6y + 6
14y − 12 = 6y + 6
Step 2: Subtract 6y from both sides.
14y − 12 6y = 6y + 6 6y
8y − 12 = 6
Step 3: Add 12 to both sides.
8y − 12 + 12 = 6 + 12
8y = 18
Step 4: Divide both sides by 8.8y/8 = 18/8
y = 9/4
Answer: y = 9/4
User Cheeseminer
by
8.6k points
4 votes
y=9/4 that's a fraction 
User Aliasbody
by
8.2k points

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