The solution to the inequality is x<121.5. Therefore, the possible values of x are any real numbers less than 121.5.
write an inequality involving the given values, let's consider the inequality:
3x+2<3+110+27+102+(x+3).
Now, let's solve this inequality for the possible values of x:
3x+2<3+110+27+102+x+3.
Combine like terms:
3x+2<245+x.
Subtract x from both sides:
2x+2<245.
Subtract 2 from both sides:
2x<243.
Divide by 2:
x<121.5.
So, the solution to the inequality is x<121.5. Therefore, the possible values of x are any real numbers less than 121.5.