Question

The sum of 5 consecutive integers is 505

Answer 1

To find the sum of 5 consecutive integers, use the formula (n + n+1 + n+2 + n+3 + n+4), where n is the first integer. The consecutive integers are 99, 100, 101, 102, and 103.

Step-by-step explanation:

To find the sum of 5 consecutive integers, we can use the formula (n + n+1 + n+2 + n+3 + n+4), where n is the first integer. In this case, the sum is 505, so we have the equation: n + (n+1) + (n+2) + (n+3) + (n+4) = 505. Simplifying this, we get: 5n + 10 = 505. Subtracting 10 from both sides gives 5n = 495. Dividing both sides by 5, we find that n = 99.

Therefore, the 5 consecutive integers are 99, 100, 101, 102, and 103.

Answer 2

using algebra:n+(n+1)+(n+2)+(n+3)+(n+4)=5055n+10=5055n=505-105n=495n=495/5n=99n+1=100n+2=101 answer