Question

Write and solve inequality for the possible values of x

Answer 1

write and solve ineggally for the possible views do

Answer 2

The solution to the inequality is x<121.5. Therefore, the possible values of x are any real numbers less than 121.5.

write an inequality involving the given values, let's consider the inequality:

3x+2<3+110+27+102+(x+3).

Now, let's solve this inequality for the possible values of x:

3x+2<3+110+27+102+x+3.

Combine like terms:

3x+2<245+x.

Subtract x from both sides:

2x+2<245.

Subtract 2 from both sides:

2x<243.

Divide by 2:

x<121.5.

So, the solution to the inequality is x<121.5. Therefore, the possible values of x are any real numbers less than 121.5.