Question

The last step is to calculate the percent by mass of each element in ammonium nitrate (NH4NO3). The masses of the elements in one mole of the compound are: mass N = 28.0 g mass H = 4.0 g mass O = 48.0 g The molar mass of the compound is 80.0 g/mol. What is the mass of one mole of the compound?

Answer 1

The last step is to calculate the percent by mass of each element in ammonium nitrate (NH4NO3). The masses of the elements in one mole of the compound are: mass N = 28.0 g mass H = 4.0 g mass O = 48.0 g The molar mass of the compound is 80.0 g/mol. What is the mass of one mole of the compound? 80.0g

Answer 2

Answer: 80 g

Step-by-step explanation:Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.

Mass of 1 mole of compound=mass of nitrogen + mass of hydrogen+ mass of oxygen= 28+4+48 = 80 g.

Percentage by mass of nitrogen=
`\frac{\text {mass of nitrogen}}{\text {Total mass}}* 100\ %`

Percentage by mass of nitrogen=
`(28)/(80)* 100\%=35\%`

Percentage by mass of hydrogen=
`\frac{\text {mass of hydrogen}}{\text {Total mass}}* 100\%`

Percentage by mass of hydrogen=
`(4)/(80)* 100\%=5\%`

Percentage by mass of oxygen=
`\frac{\text {mass of oxygen}}{\text {Total mass}}* 100\%`

Percentage by mass of oxygen=
`(48)/(80)* 100\%=60\%`