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Given right triangle def what is the value of sin e

Given right triangle def what is the value of sin e-example-1
User Dmarra
by
6.1k points

2 Answers

5 votes
right triangle
10^2 - 8^2 = 100 - 64 = 36
DF = √36
DF = 6
so
sinE = Opp / Hypo
sinE = 6/10
sinE = 3/5
User Pramod Kharade
by
6.8k points
6 votes

Answer:

Explanation:

From the given triangle DEF, we have


(EF)^(2)=(ED)^(2)+(DF)^(2)


(10)^(2)=(8)^(2)+(DF)^(2)


100-64=(DF)^2


DF=6

Now, we know that SinE=
(Perpendicular)/(Hypotenuse), thus


SinE=(DF)/(EF)


SinE=(6)/(10)=(3)/(5)

Therefore, the value of SinE is
(3)/(5).

User Tulir
by
7.7k points
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