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Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x

2 Answers

5 votes

Answer:

C. 2+_ square root 10i / 2

Explanation:

User Failsafe
by
7.8k points
2 votes
First you must rewrite the given equation in standard form:

2x^2 - 4x + 7 = 0. Here a=2, b=-4 and c=7.

The solutions are thus
-[-4] plus or minus sqrt( [-4]^2 - 4[2][7] )
x = --------------------------------------------------------
4
4 plus or minus sqrt (16 - 56)
or: x = --------------------------------------------
4

16-56 = - 40, a negative number. Thus, we must introduce the imaginary operator: sqrt (-40) = 2i*sqrt(10)

The roots are thus:
4 plus or minus 2i sqrt(10) 2 plus or minus i*sqrt(10)
x = ----------------------------------------- = ---------------------------------------
4 2
User Static Const
by
8.7k points

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