Register

Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass of the empty crucible (tare weight) was 17.410 g. …

Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass of the empty crucible (tare weight) was 17.410 g. …
25.2k views
0 votes
Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass of the empty crucible (tare weight) was 17.410 g. calculate the concentration of the ba(oh)2 solution from these data.

User Xudifsd
by
7.7k points

1 Answer

4 votes
The weight of the precipitate was 17.550g - 17.410g = 0.140g. From a 10ml sample, this means the concentration was 0.140g / 10ml, which is equal to 0.014g/ml.
User Visibleman
by
7.8k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
Why is gold preferred as a superior metal over silver and bronze?
Link Copied!