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Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass of the empty crucible (tare weight) was 17.410 g. …

Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass of the empty crucible (tare weight) was 17.410 g. …
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Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass of the empty crucible (tare weight) was 17.410 g. calculate the concentration of the ba(oh)2 solution from these data.

User Xudifsd
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The weight of the precipitate was 17.550g - 17.410g = 0.140g. From a 10ml sample, this means the concentration was 0.140g / 10ml, which is equal to 0.014g/ml.
User Visibleman
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