72.0k views
4 votes
Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is the coefficient of kinetic friction? A0.01 B0.20 C0.38 D0.48

User Jamie M
by
7.9k points

2 Answers

6 votes
The formula is Force = coefficient of friction times the weight or normal force (in newtons). Plug the numbers in the formula. Do the simple division math. The coefficient of friction should be any number between 0 and 1. If your answer is smaller than 0 or greater than 1, go back and check your work. The answer for this question is C. 0.38   
User Drew Nutter
by
8.5k points
2 votes

Answer:


\mu_k = 0.38

Step-by-step explanation:

As we know that the normal force on the book is given as


F_n = 51.7 N

also the force required to push the book on the table is given as


F_f = 19.5 N

now by the formula of friction force we know that


F_f = \mu_k F_n

now plug in all values in it


19.5 = \mu_k (51.7)

here we will have


\mu_k = (19.5)/(51.7)


\mu_k = 0.38

User Guan Yang
by
7.8k points