17.3k views
2 votes
How many moles of O2 are required for the complete reaction of 88.9 g of C2H4 to form CO2 and H2O?

1 Answer

3 votes
The molecular mass for C2H4 should be: 2*12 + 4*1= 28 gram/mol. Then the amount of mol in 88.9 grams C2H4 should be: 88.9g/ (28g/mol)= 3.175 mol.

To answer this question, you need to know the reaction formula for the problem. The formula should be:
C2H4 + 3O2 --> 2CO2 + 2H2O
In the formula, every 1 C2H4 will be reacted with 3 O2. Then the amount of oxygen needed would be: 3/1 * 3.175 mol= 9.525 mol
User Duncanwilcox
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories