Question

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form of the equation for this line?

y – 3 = –(x + 8)

y + 3 = –(x – 8) y + 8 = –(x – 3) y – 8 = –(x + 3)

Answer 1

The point-slope intercept is y - 8 = -(x + 3).  I think.

Answer 2

Option 4 -
`y-8=-(x+3)`

Explanation:

The slope-intercept form of the equation of a line that passes through point (–3, 8) is
`y =-x+ 6`.

The general form of slope intercept is
`y=mx+c`

where, m is the slope and c is the y-intercept.

On comparing,

m=-1 and c=6

The point slope form of the equation of a straight line is

`y-y_1=m(x-x_1)`

Point is
`(x_1,y_1)=(-3,8)`

Substitute the values,

`y-8=-1(x-(-3))`

`y-8=-(x+3)`

The point-slope form of the equation for this line is
`y-8=-(x+3)`

Therefore, Option 4 is correct.