Question

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? plz show me how u got the answer

Answer 1

We can model the problem using a right angle triangle.

The two sides, AB and BC are equal
By Pythagoras, we find the length of AC =
`√(1^+1^)` =
`√(2)`

Using the sin ratio ⇒ sin θ = opposite/hypotenuse, we have

`sin(45)= (1)/( √(2) )= ( √(2) )/(2)`

Using the cos ratio ⇒ cos θ = adjective/hypotenuse, we have

`cos(45)= (1)/( √(2) )= ( √(2) )/(2)`

Using the tan ratio ⇒ tan θ = opposite/adjective, we have

`tan(45)= (1)/(1)=1`