1 Answer

Carlg · Answer 1 · 2018-02-17T11:09:45+0000

The solutions to the equation are
(-5 +/- √(13))/(6)

You can find the answer to any quadratic by using the quadratic formula. The formula is below.

$\frac{-b +/- \sqrt{b^(2)-4ac}}{2a}$

Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.

$\frac{-5 +/- \sqrt{5^(2)-4(3)(1)}}{2(3)}$

(-5 +/- √(25-12))/(6)

(-5 +/- √(13))/(6)

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