Question

What is the equation of the graphed line in point-slope form?

a. y – 1 = (x + 3)
b. y – 1 = (x – 3)
c. y + 1 = (x – 3)
d. y + 1 = (x + 3)

Answer 1

(3,1)(-3,-3)
slope = (-3 - 1) / (-3 - 3) = -4/-6 = 2/3

y - y1 = m(x - x1)
slope(m) = 2/3
(3,1)...x1 = 3 and y1 = 1
now we sub
y - 1 = 2/3(x - 3) <==

Answer 2

`y-1 = (2)/(3)(x-3)`

Explanation:

To find the equation of graphed line we pick two points from the line

(3,1) and (-3,-3)

Equation of a line is y=mx+b

where 'm' is the slope and b is the y intercept

slope
`m= (y2-y1)/(x2-x1) =(1+3)/(3+3) = (2)/(3)`

we use point slope formula

y-y1= m(x-x1)

here point(x1,y1) is (3,1) and slope m = 2/3

Plug in all the value

`y-1 = (2)/(3) (x-3)`