Question

Any help would be really appreciated!

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parentheses 6 minus 6 i close parentheses.

A: -3 - 6i/5
B: 39 - 6i/-9
C: -39 - 6i/ 17
D: 3 - 6i/3

(The first pic attached is the actual equation and the next are the potential answers)

Answer 1

`(√(-9))/((4-7i)-(6-6i))=\\ (√(9*i^2))/(-2-i)=\\ (3i)/(-2+i)*(-2+i)/(-2+i)=\\ (3i*(-2+i))/((-2-i)*(-2+i))=\\ (-6i+3i^2)/(4-i^2)=\\ (-3-6i)/(4+1)=\\ (-3-6i)/(5)\\`

so it is the first option