Question

Barium sulfate is a compound used to assist in diagnosing medical problems through x-ray analysis and is 58.8% barium. what mass of barium is present in a 620 mg tablet of barium sulfate?

Answer 1

To find the mass of barium in a 620 mg tablet of barium sulfate, multiply the tablet's mass by the percentage of barium (58.8%). The calculation yields approximately 364.56 mg of barium in the tablet.

Step-by-step explanation:

The question is asking to calculate the mass of barium present in a 620 mg tablet of barium sulfate, a compound known for its use in medical imaging. Given that barium sulfate is 58.8% barium by mass, we can calculate the mass of barium in the tablet by multiplying the total mass of the tablet by the percentage of barium.

To find the amount of barium, we use the following calculation:

Mass of barium = (mass of barium sulfate tablet) x (percentage of barium) / 100%

Mass of barium = (620 mg) x (58.8%) / 100

Mass of barium = 620 mg x 0.588

Mass of barium ≈ 364.56 mg

Therefore, a 620 mg tablet of barium sulfate contains approximately 364.56 mg of barium.

Answer 2

In barium sulfate, there is only 58.8% barium mass out of the total mass. From this description you can get this equation:
barium mass= barium sulfate mass * 58.8%

In this question, you are asked the mass of barium in 620mg barium sulfate. Then, the answer would look like this
barium mass= barium sulfate mass * 58.8%
barium mass= 620mg* 58.8%
barium mass= 364.56mg