Question

A 10.1 kg bowling ball and a 8.4 kg bowling ball rest on a rack 1.25 m apart. What is the gravitational force exerted between them?

Answer 1

The gravitational force between the two bowling balls is approximately 3.732 × 10^-10 N.

Step-by-step explanation:

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation:

F = (G * m1 * m2) / r^2

Where F is the gravitational force, G is the gravitational constant (6.674 × 10^-11 N·m² kg^2), m1 and m2 are the masses of the objects, and r is the distance between their centers.

Given that the masses of the two bowling balls are 10.1 kg and 8.4 kg, and they are 1.25 m apart, we can substitute these values into the formula to calculate the gravitational force between them:

F = (6.674 × 10^-11 * 10.1 * 8.4) / (1.25^2)

= 3.732 × 10^-10 N

So, the gravitational force exerted between the two bowling balls is approximately 3.732 × 10^-10 N.

Answer 2

Given data:

* The mass of the first bowling ball is 10.1 kg.

* The mass of the second bowling ball is 8.4 kg.

* The distance between the bowling balls is 1.25 m.

Solution:

The gravitational force between the bowling balls is,

`F=(Gm_1m_2)/(r^2)`

where G is the graviatational constant, m_1 is the mass of first bowling ball, m_2 is the mass of second bowling ball, and r is the distance between the bowling balls,

`\begin{gathered} F=(6.67*10^(-11)*10.1*8.4)/(1.25^2) \\ F=362.16*10^(-11)\text{ N} \end{gathered}`

Thus, the gravitational force acting between the bowling balls is,

`362.16*10^(-11)\text{ N}`